A strengthened truncated-mean inequality for sums of uniform random variables
A strengthened truncated-mean inequality for sums of uniform random variables
Let be independent uniform random variables on , and set
For , define the truncated mean
Strengthened truncated-mean inequality. For every ,
This is presented as a stronger inequality motivated by numerical experiments; the supplied text gives no resolution status.
Progress summary
No public discussion or published progress on this inequality was found.
No public discussion or published progress addressing this specific inequality was found.
Current status (as of August 2026): The problem appears open, with no recorded activity or verified result.
Sources & referencesView supporting material
Primary source
Shoni Gilboa, Pazit Haim-Kislev and Boaz Slomka, “Isobarycentric Inequalities”, arXiv:2202.07527 (2022).
Solutions 1
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The conjecture holds for every and every . In fact, there is an exact positive-deficit identity, and the constant is sharp.
Write
and define
We prove
For , integration by parts gives
since the boundary term vanishes at . Apply this conditionally in coordinate to
almost everywhere. Summing over the independent coordinates yields
Divide by . The left side becomes
Meanwhile,
so the right side of (2), after conditioning, becomes
Equating these expressions proves (1).
Every nonempty upper tail has strictly positive conditional variance , while and . Therefore
This is precisely the conjecture, with an explicit strictness gap.
Finally, if and , the coordinate deficits , conditioned on , are uniformly distributed on
Hence
and
Thus the conjectured constant is best possible for every .
Source: S. Gilboa, P. Haim-Kislev and B. Slomka, Isobarycentric Inequalities, International Mathematics Research Notices 2023(14), 12298–12323, doi:10.1093/imrn/rnac191; arXiv:2202.07527, Conjecture 1.5.