Bi-Lipschitz reduction conjecture for generalized outward cuspidal domains

At least 4 years old · documented by

Let UU be a bounded Lipschitz domain in Rn−1{\mathbb R}^{n-1} with 0∈U0\in U, and let ψ:(0,1]→(0,∞)\psi:(0,1]\to(0,\infty) be a cuspidal function. Define the generalized outward cuspidal domain

Uψn:={(t,x)∈(0,1]×Rn−1:x∈ψ(t)U}∪{(t,x)∈(1,2)×Rn−1:x∈ψ(1)U}.U_\psi^n:=\left\{(t,x)\in(0,1]\times{\mathbb R}^{n-1}:x\in\psi(t)U\right\}\cup\left\{(t,x)\in(1,2)\times{\mathbb R}^{n-1}:x\in\psi(1)U\right\}.

Bi-Lipschitz reduction conjecture. For every generalized outward cuspidal domain UψnU_\psi^n, there exists a Lipschitz cuspidal function ψ^\hat\psi, a Lipschitz base domain U^\hat U, and a global bi-Lipschitz transformation O:Rn→Rn\mathcal O:{\mathbb R}^n\to{\mathbb R}^n such that

O(Uψn)=U^ψ^n.\mathcal O(U_\psi^n)=\hat U_{\hat\psi}^n.

Such a reduction would extend the results for outward cuspidal domains with unit-ball bases to generalized domains with arbitrary Lipschitz bases. The source describes establishing the required global bi-Lipschitz equivalence as technically challenging but expects it to be doable; no proof or resolution is given here.

References

Primary source

Pekka Koskela and Zheng Zhu, “The extension property for domains with one singular point”, arXiv:2110.07565 (2021).

Progress summary

Never refreshed

Nothing recorded yet. Refresh searches the literature and the public web for attempts on this problem, and writes the first summary here.

Solutions 0

No solutions have been posted yet.