Generalized Mazya conjecture for weakly cancelling Fourier multipliers

Let T ⁣:Sd1R\mathrm{T}\colon S^{d-1}\to\mathbb{R}^{\ell} be sufficiently smooth, at least Hölder continuous, and weakly cancelling:

Sd1T(ζ)dσ(ζ)=0.\int_{S^{d-1}}\mathrm{T}(\zeta)\,d\sigma(\zeta)=0.

For α(0,d)\alpha\in(0,d), define

Tα[f]=F1(T(ξ/ξ)f^(ξ)ξα),\mathbb{T}_\alpha[f]=\mathcal{F}^{-1}\left(\frac{\mathrm{T}(\xi/|\xi|)\widehat f(\xi)}{|\xi|^\alpha}\right),

let T~\widetilde{\mathrm{T}} be determined by

T~(x)xdα=F1(T(ξ/ξ)ξα)(x),\frac{\widetilde{\mathrm{T}}(x)}{|x|^{d-\alpha}}=\mathcal{F}^{-1}\left(\frac{\mathrm{T}(\xi/|\xi|)}{|\xi|^\alpha}\right)(x),

and choose pp so that p1p=αd\frac{p-1}{p}=\frac{\alpha}{d}. Let Φ ⁣:RR\Phi\colon\mathbb{R}^{\ell}\to\mathbb{R} be positively pp-homogeneous and locally Lipschitz. Generalized Mazya conjecture. The estimate

RdΦ(Tα[f](x))dxfL1p\left|\int_{\mathbb{R}^d}\Phi(\mathbb{T}_\alpha[f](x))\,dx\right|\lesssim\|f\|_{L_1}^p

holds for all compactly supported ff with f=0\int f=0, with a uniform constant, if and only if

Sd1Φ(T~(x))dσ(x)=0.\int_{S^{d-1}}\Phi(\widetilde{\mathrm{T}}(x))\,d\sigma(x)=0.

The question generalizes Mazya's conjecture to fractional, vector-valued Fourier multipliers and is posed as an open question from the Bellman-function viewpoint; the source gives no resolution.

Sources & referencesView supporting material

Primary source

Dmitriy Stolyarov, “On Φ-inequalities for martingale fractional integration and their Bellman functions”, arXiv:2107.09336 (2021).

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