Powerfree preservation conjecture for the sum-of-proper-divisors function

From papers

Let s(n):=dn, d<nds(n):=\sum_{d\mid n,\ d<n}d be the sum-of-proper-divisors function. Fix k2k\ge 2, and call a positive integer kk-free if it is not divisible by the kkth power of any integer greater than 11.

Powerfree preservation conjecture. On a set of integers nn of asymptotic density 11,

n is k-frees(n) is k-free.\text{$n$ is $k$-free} \Longleftrightarrow \text{$s(n)$ is $k$-free}.

The conjecture predicts that, for every fixed k2k\ge 2, the sum-of-proper-divisors function preserves kk-freeness for almost all integers. The preceding discussion explains that small prime-power divisors are controlled by results on the divisibility of σ(n)\sigma(n); the remaining issue is to exclude large prime-power divisors of s(n)s(n) for almost all nn.

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Sources & referencesView supporting material

Primary source

Paul Pollack and Akash Singha Roy, “Powerfree sums of proper divisors”, arXiv:2106.14953 (2021).

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