Gromov's square inequality for spin manifolds with cube-like boundaries

Let (X,g)(X,g) be an nn-dimensional compact connected orientable manifold with boundary, and let X\underline{X}_\bullet be a closed orientable manifold of dimension nmn-m. Suppose

f ⁣:X[1,1]m×Xf\colon X\to[-1,1]^m\times\underline{X}_\bullet

is a continuous map sending the boundary of XX to the boundary of [1,1]m×X[-1,1]^m\times\underline{X}_\bullet and having non-zero degree. Let j±\partial_{j\pm}, j=1,,mj=1,\dots,m, be the pullbacks of the pairs of opposite faces of [1,1]m[-1,1]^m under the composition with the projection to [1,1]m[-1,1]^m. Assume that for any mm hypersurfaces YjXY_j\subset X separating j\partial_{j-} from j+\partial_{j+}, their transversal intersection YY_\pitchfork does not admit a metric with positive scalar curvature, and neither do Y×TkY_\pitchfork\times T^k for any kk-dimensional torus. If Sc(g)n(n1)\operatorname{Sc}(g)\geq n(n-1), set j=dist(j,j+)\ell_j=\operatorname{dist}(\partial_{j_-},\partial_{j_+}). Gromov's square inequality. Then

j=1m1j2n24π2,\sum_{j=1}^m\frac{1}{\ell_j^2}\geq\frac{n^2}{4\pi^2},

and consequently

min1jmdist(j,j+)m2πn.\min_{1\leq j\leq m}\operatorname{dist}(\partial_{j_-},\partial_{j_+})\leq\sqrt{m}\,\frac{2\pi}{n}.

The result is a conjectural statement in the relevant high-dimensional cases: the paper proves it in the spin case with a suboptimal constant, while Gromov's original minimal-surface proof in dimensions at least 99 depends on unpublished or generalized results. It gives scalar-curvature obstructions to large distances between opposite faces of cube-like boundaries.

Sources & referencesView supporting material

Primary source

Zhizhang Xie, “A quantitative relative index theorem and Gromov's conjectures on positive scalar curvature”, arXiv:2103.14498 (2021).

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