A p-adic supercongruence for a Ramanujan-type sum

Let $p\equiv 5\pmod{8}$ be a prime, and let $(a)_k=a(a+1)\cdots(a+k-1)$ denote the rising factorial. The p-adic supercongruence conjecture.

$$\sum_{k=0}^{p-1}(12 k+1) \frac{(\frac{1}{4})_{k}^{2}(\frac{1}{8})_{k}}{4^{k} k !^{3}} \equiv 0 \pmod {p^3}.$$

This is presented as a stronger version of a previously proved congruence modulo $p^2$, based on numerical calculations; its status is open in the source.