The solvable-group supremum conjecture for odd exponents

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Let nn be a positive integer, let S\mathcal{S} be the class of finite solvable groups, and for H∈SH\in\mathcal{S} and ϕ∈Aut⁡(H)\phi\in\operatorname{Aut}(H) define

Xn,ϕ(H):={x∈H∣xxϕxϕ2⋯xϕn−1=1}.X_{n,\phi}(H):=\left\{x\in H\mid xx^\phi x^{\phi^2}\cdots x^{\phi^{n-1}}=1\right\}.

Solvable-group supremum conjecture. For every positive integer nn, one has

c2n+1S:=sup⁡({∣Xn,ϕ(H)∣∣H∣:H∈S, ϕ∈Aut⁡(H), ϕ2n+1=id⁡}∖{1})<1.c^{\mathcal S}_{2n+1}:=\sup\left(\left\{\frac{|X_{n,\phi}(H)|}{|H|}: H\in\mathcal S,\ \phi\in\operatorname{Aut}(H),\ \phi^{2n+1}=\operatorname{id}\right\}\setminus\{1\}\right)<1.

For odd exponents, the paper states that this conjecture is equivalent to the Lé vai–Pyber conjecture; no general proof is supplied.

References

Primary source

Alireza Abdollahi and Meisam Soleimani Malekan, “Profinite groups with many elements of bounded order”, arXiv:2012.13886 (2021).

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