Pieropan–Smeets–Tanimoto–Várilly-Alvarado counting conjecture for Campana points

About 6 years old · traced to

Let KK be a number field, let (X,Dϵ)(X,D_{\epsilon}) be a smooth klt Fano Campana orbifold over KK, and let (X,Dϵ)(\mathcal{X},\mathcal{D}_{\epsilon}) be a regular OK,S\mathcal{O}_{K,S}-model for a finite set SS of places containing S∞S_{\infty}. Let L=(L,∥⋅∥)\mathcal{L}=(L,\|\cdot\|) be an adelically metrised big line bundle with height function HLH_{\mathcal{L}}, and write

N(U,L,B)=#{P∈U:HL(P)≤B}.N(U,\mathcal{L},B)=\#\{P\in U:H_{\mathcal{L}}(P)\leq B\}.

For a variety VV over a characteristic-zero field and a subset A⊂V(k)A\subset V(k), recall that AA is thin if it is contained in a finite union of subsets of types I and II, where type I means containment in the kk-points of a proper Zariski closed subset and type II means containment in the image of the kk-points of a finite surjective morphism of degree at least 22 from a normal geometrically irreducible variety of the same dimension. Pieropan–Smeets–Tanimoto–Várilly-Alvarado conjecture. Suppose that LL is nef and (X,Dϵ)(OK,S)(\mathcal{X},\mathcal{D}_{\epsilon})(\mathcal{O}_{K,S}) is not thin. Then there exists a thin set Z⊂(X,Dϵ)(OK,S)Z\subset (\mathcal{X},\mathcal{D}_{\epsilon})(\mathcal{O}_{K,S}) and explicit positive constants a=a((X,Dϵ),L)a=a((X,D_{\epsilon}),L), b=b(K,(X,Dϵ),L)b=b(K,(X,D_{\epsilon}),L), and c=c(K,S,(X,Dϵ),L,Z)c=c(K,S,(\mathcal{X},\mathcal{D}_{\epsilon}),\mathcal{L},Z) such that, as B→∞B\to\infty,

N((X,Dϵ)(OK,S)∖Z,L,B)∼cBa(log⁡B)b−1.N\bigl((\mathcal{X},\mathcal{D}_{\epsilon})(\mathcal{O}_{K,S})\setminus Z,\mathcal{L},B\bigr)\sim cB^a(\log B)^{b-1}.

This is a Manin-type asymptotic for Campana points, predicting polynomial-logarithmic growth after removing a thin exceptional set. The supplied source gives no evidence resolving the conjecture, so its status remains open.

References

Primary source

Sam Streeter, “Campana points and powerful values of norm forms”, arXiv:2009.01106 (2022).

Progress summary

Never refreshed

Nothing recorded yet. Refresh searches the literature and the public web for attempts on this problem, and writes the first summary here.

Solutions 0

No solutions have been posted yet.