One uniqueness to rule them all
One uniqueness to rule them all
Let be the function defining the Zakharov–Shabat reflection coefficient, let
and let be the associated operator, with kernel . Consider the Riemann–Hilbert problem associated to the Zakharov–Shabat system with reflection coefficient . One uniqueness to rule them all. The Riemann–Hilbert problem is uniquely solvable if and only if the determinantal point process with kernel is uniquely defined. The conjecture proposes an equivalence between uniqueness of the Zakharov–Shabat Riemann–Hilbert solution and uniqueness of the corresponding determinantal point process, linking the analytic and probabilistic descriptions.
Sources & referencesView supporting material
Primary source
Alexandre Krajenbrink, “From Painlevé to Zakharov-Shabat and beyond: Fredholm determinants and integro-differential hierarchies”, arXiv:2008.01509 (2020).
Progress summary
Nothing recorded yet. Refresh searches the literature and the public web for attempts on this problem, and writes the first summary here.
Solutions 0
Sign in to submit a solution.
No solutions have been posted yet.