The Kazhdan–Lusztig character conjecture at negative level

About 13 years old · traced to

Let g\mathfrak g be a symmetrizable complex Kac–Moody algebra with Weyl group W\mathcal W and simple reflections S\mathcal S. Fix a Weyl vector ρ\rho, let w.λ=w(λ+ρ)−ρw.\lambda=w(\lambda+\rho)-\rho be the dot action, and let ⩽\leqslant be the usual partial order on weights. For a weight λ\lambda, call it non-critical when 2(λ+ρ,δ)∉Z(δ,δ)2(\lambda+\rho,\delta)\notin\mathbb Z(\delta,\delta) for every imaginary root δ\delta, integral when ⟨λ,α∨⟩∈Z\langle\lambda,\alpha^\vee\rangle\in\mathbb Z for every simple root α\alpha, regular when w.λ=λw.\lambda=\lambda implies w=ew=e, and anti-dominant when ⟨λ,α∨⟩∉Z≥0\langle\lambda,\alpha^\vee\rangle\notin\mathbb Z_{\geq 0} for every simple root α\alpha. Let L(λ)L(\lambda) be the irreducible highest-weight representation and Δ(μ)\Delta(\mu) the Verma module of highest weight μ\mu. Kazhdan–Lusztig character conjecture. Suppose λ\lambda is non-critical, integral, regular and anti-dominant. For every w∈Ww\in\mathcal W,

ch⁡L(w.λ)=∑y⩽w(−1)l(w)−l(y)Py,w(1)ch⁡Δ(y.λ),\operatorname{ch} L(w.\lambda)=\sum_{y\leqslant w}(-1)^{l(w)-l(y)}P_{y,w}(1)\operatorname{ch}\Delta(y.\lambda),

where Py,w∈Z[v]P_{y,w}\in\mathbb Z[v] is the Kazhdan–Lusztig polynomial associated with yy and ww for the Coxeter system (W,S)(\mathcal W,\mathcal S). This generalizes the affine negative-level conjecture, which was proved by Kazhdan and Lusztig; the stated generalization is resolved in the source context.

References

Primary source

Giovanna Carnovale, Francesco Esposito and Peter Fiebig, “Localization of IC-complexes on Kashiwara's flag scheme and representations of Kac-Moody algebras”, arXiv:2004.08943 (2021).

Additional references

2 papers in this index state this conjecture (2013–2020). The statement above is taken from the most recent of them; the others are arXiv:1308.2873.

Progress summary

Never refreshed

Nothing recorded yet. Refresh searches the literature and the public web for attempts on this problem, and writes the first summary here.

Solutions 0

No solutions have been posted yet.