A second q-analogue of the Swisher-type supercongruence

Define the $q$-shifted factorial by $(a;q)_0=1$ and $(a;q)_k=(1-a)(1-aq)\cdots(1-aq^{k-1})$ for $k\geq 1$, let $\Phi_n(q)$ be the $n$-th cyclotomic polynomial, and write $[n]=1+q+\cdots+q^{n-1}$. Let $n$ be a positive integer with $n\equiv 3\;\allowbreak(\operatorname{mod}4)$. The second q-analogue conjecture. Modulo $\Phi_n(q)^2\Phi_{n^2}(q)^2$,

$$\sum_{k=0}^{(n^2-1)/2}\frac{(q;q^2)_k^2(q^2;q^4)_k}{(q^2;q^2)_k^2(q^4;q^4)_k}q^{2k}\equiv \frac{[n^2](q^3;q^4)_{(n^2-1)/2}}{(q^5;q^4)_{(n^2-1)/2}},$$ $$\sum_{k=0}^{n^2-1}\frac{(q;q^2)_k^2(q^2;q^4)_k}{(q^2;q^2)_k^2(q^4;q^4)_k}q^{2k}\equiv \frac{[n^2](q^3;q^4)_{(n^2-1)/2}}{(q^5;q^4)_{(n^2-1)/2}}.$$

The conjecture is motivated by the preceding q-congruence and is proposed as a q-analogue of the two displayed Swisher-type congruences. The supplied text gives no resolution status.