The invariant little Grothendieck conjecture for invariant function spaces

Let GG be a compact abelian group, let Z(G)Z(G) be an invariant function space, and let T:H1H2T:H_1\to H_2 be an operator between Hilbert spaces. Say that TT factorizes invariantly through Z(G)Z(G) if there are orthonormal bases (hn,1)(h_{n,1}) and (hn,2)(h_{n,2}) of H1H_1 and H2H_2, operators A:H1Z(G)A:H_1\to Z(G) and B:Z(G)H2B:Z(G)\to H_2 with T=BAT=B\circ A, and an enumeration (γn)(\gamma_n) of the characters of GG such that A(hn,1)spanγnA(h_{n,1})\in\operatorname{span}\gamma_n and B(γn)spanhn,2B(\gamma_n)\in\operatorname{span}h_{n,2} for n=1,2,n=1,2,\dots. Invariant little Grothendieck conjecture. If Z(G)Z(G) has no complemented, invariant infinite-dimensional subspaces isomorphic to a Hilbert space, then every Hilbert space operator TT that factorizes invariantly through Z(G)Z(G) belongs to some nontrivial Schatten class. The claim abstracts the Sobolev-space question to invariant function spaces; the paper presents it as the conjectural interpretation motivating its harmonic-analysis result, while the invariant little Grothendieck theorem for L1L_1 is noted as known.

Sources & referencesView supporting material

Primary source

Krystian Kazaniecki, Piotr Pakosz and Michał Wojciechowski, “An invariant variant of the little Grothendieck theorem for Sobolev spaces”, arXiv:1912.00686 (2020).

Progress summary

Never refreshed

Nothing recorded yet. Refresh searches the literature and the public web for attempts on this problem, and writes the first summary here.

Solutions 0

No solutions have been posted yet.