Rémond's generalized Lehmer conjecture

Let G\mathcal{G} be either a torus or an abelian variety defined over a number field KK, and let Γ\Gamma be a finite rank subgroup of G(Q)\mathcal{G}(\overline{\mathbb{Q}}). Write Γsat\Gamma_{\operatorname{sat}} for the saturation of Γ\Gamma under the endomorphisms of G\mathcal{G} and divisibility, and call αG(Q)\alpha\in\mathcal{G}(\overline{\mathbb{Q}}) Γ\Gamma-transversal if it lies in a translate γ+B\gamma+B with γΓsat\gamma\in\Gamma_{\operatorname{sat}} and BB a connected proper algebraic subgroup of G\mathcal{G}. Let h^G\widehat{h}_{\mathcal{G}} denote the canonical height and let dim(G)\dim(\mathcal{G}) be the dimension of G\mathcal{G}.

Rémond's generalized Lehmer conjecture. The following assertions hold:

(a) There exists a positive constant cc such that

h^G(α)c[K(Γsat)(α):K(Γsat)]1/dim(G)\widehat{h}_{\mathcal{G}}(\alpha)\geq \frac{c}{[K(\Gamma_{\operatorname{sat}})(\alpha):K(\Gamma_{\operatorname{sat}})]^{1/\dim(\mathcal{G})}}

for every αG(Q)\alpha\in\mathcal{G}(\overline{\mathbb{Q}}) that is not Γ\Gamma-transversal.

(b) For every ε>0\varepsilon>0 there exists a positive constant cεc_{\varepsilon} such that

h^G(α)cε[K(Γsat)(α):K(Γsat)]1/dim(G)+ε\widehat{h}_{\mathcal{G}}(\alpha)\geq \frac{c_{\varepsilon}}{[K(\Gamma_{\operatorname{sat}})(\alpha):K(\Gamma_{\operatorname{sat}})]^{1/\dim(\mathcal{G})+\varepsilon}}

for every αG(Q)\alpha\in\mathcal{G}(\overline{\mathbb{Q}}) that is not Γ\Gamma-transversal.

(c) For every finite extension L/K(Γsat)L/K(\Gamma_{\operatorname{sat}}) there exists a positive constant cLc_L such that

h^G(α)cL\widehat{h}_{\mathcal{G}}(\alpha)\geq c_L

for every αG(L)Γsat\alpha\in\mathcal{G}(L)\setminus\Gamma_{\operatorname{sat}}.

Sources & referencesView supporting material

Primary source

Lukas Pottmeyer, “Fields Generated by Finite Rank Subgroups of Q^*”, arXiv:1910.11636 (2020).

Progress summary

Never refreshed

Nothing recorded yet. Refresh searches the literature and the public web for attempts on this problem, and writes the first summary here.

Solutions 0

No solutions have been posted yet.