Ordinary implies ordinary Galois representations

Let FF) be an imaginary quadratic field, let m\mathfrak{m} be a non-Eisenstein maximal ideal of residue characteristic p>2p>2 associated to a residual Galois representation ρ\overline{\rho}, and suppose that TvmT_v\notin\mathfrak{m} for every vpv\mid p. Let L\mathcal{L} have parallel weight (k,k)(k,k) with k2k\geq 2, and let TQ,m\mathbf{T}_{Q,\mathfrak{m}} be the localized Hecke algebra. Ordinary \Rightarrow Ordinary. There exists a continuous Galois representation

ρ=ρm:GFGL2(TQ,m)\rho=\rho_{\mathfrak{m}}:G_F\longrightarrow \operatorname{GL}_2(\mathbf{T}_{Q,\mathfrak{m}})

with the following properties: for λRQ{vp}S\lambda\notin R\cup Q\cup\{v\mid p\}\cup S, it is unramified at λ\lambda and the characteristic polynomial of ρ(Frobλ)\rho(\operatorname{Frob}_{\lambda}) is

Y2TλX+NF/Q(λ)k1TQ,m[X];Y^2-T_{\lambda}X+N_{F/\mathbf{Q}}(\lambda)^{k-1}\in\mathbf{T}_{Q,\mathfrak{m}}[X];

for vpv\mid p, ρDv\rho|D_v is ordinary with eigenvalue the unit root of X2TvX+N(v)k1X^2-T_vX+N(v)^{k-1}; for vRv\in R and vSv\in S, its restriction to inertia is unipotent, with the stated Frobenius characteristic polynomial at vSv\in S; for vQv\in Q, under the stated invertibility, residual unramifiedness, and condition ϕ(Frobv)≢±1(modm)\phi(\operatorname{Frob}_v)\not\equiv\pm1\pmod{\mathfrak{m}}, one has ρDvϕϵϕ1\rho|D_v\sim\phi\epsilon\oplus\phi^{-1}; and if k=2k=2 and the level is prime to vpv\mid p, then ρDv\rho|D_v is finite flat. This asserts that the ordinary Hecke-theoretic data give rise to an ordinary Galois representation with the prescribed local properties. The statement is presented as the paper's main assumption on the existence of Galois representations; no resolution status is supplied in the source.

Sources & referencesView supporting material

Primary source

Frank Calegari, “Semistable modularity lifting over imaginary quadratic fields”, arXiv:1907.08700 (2019).

Progress summary

Never refreshed

Nothing recorded yet. Refresh searches the literature and the public web for attempts on this problem, and writes the first summary here.

Solutions 0

No solutions have been posted yet.