Del Zotto–Lockhart's conjecture for rank-one instanton strings

Let GG be the global symmetry group of a rank-one HGH_G theory, let vv and mGm_G denote its fugacities, and let QτQ_{\tau} be the elliptic-parameter fugacity. Write

LG(1)(v,mG,Qτ)=i,j=0bi,jGQτivj.L_{G}^{(1)}(v,m_G,Q_{\tau})=\sum_{i,j=0}^{\infty}b^G_{i,j}Q_{\tau}^iv^j.

Let EhG(1)(v)\mathbb{E}_{h_G^{(1)}}(v) denote the reduced one-string elliptic genus, set h=hG/6h=h_G^\vee/6, and define u=v/Qτ1/4u=v/Q_{\tau}^{1/4}. Del Zotto–Lockhart's conjecture. There exists such a function LG(1)L_G^{(1)} satisfying: each bi,jGb^G_{i,j} is a sum of characters of irreducible representations of GG with integral coefficients; LG(1)(v,mG,0)L_G^{(1)}(v,m_G,0) is the Hilbert series of the reduced moduli space of one GG-instanton, equivalently the Hall–Littlewood index of the HG(1)H_G^{(1)} theory; LG(1)(q1/2,mG,q2)L_G^{(1)}(q^{1/2},m_G,q^2) is the Schur index of the HG(1)H_G^{(1)} theory; and EhG(1)(v)\mathbb{E}_{h_G^{(1)}}(v) is generated from LG(1)(v)L_G^{(1)}(v) by the formula

EhG(1)(v)=v2h1Qτ1/6n0Qτ2n[u4hLG(Qτnv)(1)2hu4hLG(Qτn+1/2/v)+(1+(1)2h)Qτh+1/2(u2LG(Qτn+1/2v)u2LG(Qτn+1/v))+Qτ2((1)2hu4(1h)LG(Qτn+1v)u4(1h)LG(Qτn+3/2/v))].\mathbb{E}_{h_G^{(1)}}(v)=v^{2h-1}Q_{\tau}^{1/6}\sum_{n\geq0}Q_{\tau}^{2n}\bigg[u^{4h}L_G(Q_{\tau}^n v)-(-1)^{2h}u^{-4h}L_G(Q_{\tau}^{n+1/2}/v)+(1+(-1)^{2h})Q_{\tau}^{h+1/2}\left(u^2L_G(Q_{\tau}^{n+1/2}v)-u^{-2}L_G(Q_{\tau}^{n+1}/v)\right)+Q_{\tau}^2\left((-1)^{2h}u^{4(1-h)}L_G(Q_{\tau}^{n+1}v)-u^{-4(1-h)}L_G(Q_{\tau}^{n+3/2}/v)\right)\bigg].

This conjecture proposes a common structure relating one-string elliptic genera to the Hilbert series and supersymmetric indices of rank-one HGH_G theories. Its resolution is not specified in the source.

Sources & referencesView supporting material

Primary source

Jie Gu, Albrecht Klemm, Kaiwen Sun and Xin Wang, “Elliptic Blowup Equations for 6d SCFTs. II: Exceptional Cases”, arXiv:1905.00864 (2019).

Progress summary

Never refreshed

Nothing recorded yet. Refresh searches the literature and the public web for attempts on this problem, and writes the first summary here.

Solutions 0

No solutions have been posted yet.