Parity formula for the Kepler limit of pλp_\lambda

About 7 years old · traced to

Let p=pλp=p_\lambda be the polynomial family considered in the paper, and let γ(p)\gamma(p) denote the quantity defined in the preceding observation. Parity formula for pλp_\lambda. For polynomials of the form p=pλp=p_\lambda, the statements in the preceding observation hold for all k≥5k\geq 5. In particular, the preceding observation asserts that γ(p)=1\gamma(p)=1 for odd kk and γ(p)=2\gamma(p)=2 for even kk. This extends computations carried out for 5≤k≤5005\leq k\leq 500; no proof or resolution is supplied in the given text.

References

Primary source

Barry Brent, “Hecke groups, linear recurrences, and Kepler limits”, arXiv:1903.00419 (2021).

Progress summary

Never refreshed

Nothing recorded yet. Refresh searches the literature and the public web for attempts on this problem, and writes the first summary here.

Solutions 0

No solutions have been posted yet.