The conjecture that the maximal order of S(t) is one half

About 8 years old · traced to

Let N(t)N(t) count the nontrivial zeros of the Riemann zeta function up to height tt, and define S(t)S(t) by

N(t)=t2πlog⁡(t2πe)+78+S(t)+O(1/t).N(t)=\frac{t}{2\pi}\log \Big(\frac{t}{2\pi e}\Big)+\frac{7}{8}+S(t)+O(1/t).

Define

α=lim sup⁡t→∞log⁡∣S(t)∣log⁡log⁡t.\alpha=\limsup_{t\to\infty}\frac{\log |S(t)|}{\log\log t}.

The maximal-order conjecture for S(t)S(t). Conditionally on the Riemann hypothesis,

α=1/2.\alpha=1/2.

The source records the conditional bounds 1/2≤α≤11/2\leq\alpha\leq 1 and explains that the conjecture identifies the expected true maximal order of the zero-counting remainder. The source does not state that this conjecture has been resolved.

References

Primary source

Winston Heap, “A note on the maximum of the Riemann zeta function on the 1-line”, arXiv:1812.01415 (2018).

Progress summary

Never refreshed

Nothing recorded yet. Refresh searches the literature and the public web for attempts on this problem, and writes the first summary here.

Solutions 0

No solutions have been posted yet.