Fibonacci multiplier conjecture for permuted van der Corput sequences

About 8 years old · traced to

Let pn=Fnp_n=\mathfrak{F}_n be the nnth Fibonacci number and let μn=σpn−1,0\mu_n=\sigma_{p_{n-1},0}. Define z(1)=z(2)=z(3)=1z(1)=z(2)=z(3)=1, z(4)=2z(4)=2, and, for subsequent indices, z(n)=z(n−1)+z(n−3)+z(n−4)z(n)=z(n-1)+z(n-3)+z(n-4). Fibonacci multiplier conjecture. The maximum of the discrepancy function satisfies

max⁡x∈[0,1]ψpnμn(x)=ψpnμn(z(n−2)pn)=ψpnμn(z(n−1)pn).\max_{x\in[0,1]}\psi_{p_n}^{\mu_n}(x)=\psi_{p_n}^{\mu_n}\left(\frac{z(n-2)}{p_n}\right)=\psi_{p_n}^{\mu_n}\left(\frac{z(n-1)}{p_n}\right).

Moreover, the dominant interval is

[z(n−2)pn,z(n−2)+1pn],\left[\frac{z(n-2)}{p_n},\frac{z(n-2)+1}{p_n}\right],

and

αpnμn=lim⁡m→∞1m∑j=1mψpnμn(x^nbj),x^n=∑m=1∞z(n−2)bm.\alpha_{p_n}^{\mu_n}=\lim_{m\to\infty}\frac{1}{m}\sum_{j=1}^m\psi_{p_n}^{\mu_n}(\hat{x}_n b^j),\qquad \hat{x}_n=\sum_{m=1}^{\infty}\frac{z(n-2)}{b^m}.

These Fibonacci-based affine permutations are motivated by the continued-fraction behavior of consecutive Fibonacci ratios and the expected optimality of the golden-ratio rotation. The assertions are numerical observations presented as a conjecture; no general proof is given.

References

Primary source

Florian Pausinger, “On the intriguing search for good permutations”, arXiv:1806.05508 (2018).

Progress summary

Never refreshed

Nothing recorded yet. Refresh searches the literature and the public web for attempts on this problem, and writes the first summary here.

Solutions 0

No solutions have been posted yet.