Exceptional-set growth conjecture for Goldbach representations in progressions

Assume mm is even, and let (Z/mZ)×(\mathbb Z/m\mathbb Z)^\times denote the invertible residue classes. For admissible a,b(Z/mZ)×a,b\in(\mathbb Z/m\mathbb Z)^\times, let Ea,b,mE_{a,b,m} be the set of positive even na+b(modm)n\equiv a+b\pmod m that cannot be written as n=p+qn=p+q with primes pa(modm)p\equiv a\pmod m and qb(modm)q\equiv b\pmod m. Define

Emax(m):=max{nEa,b,m:a,b(Z/mZ)×}E_{\max}(m):=\max\{n\in E_{a,b,m}:a,b\in(\mathbb Z/m\mathbb Z)^\times\}

and

Lavg(m):=1ϕ(m)2a,b(Z/mZ)×Ea,b,m.L_{\mathrm{avg}}(m):=\frac{1}{\phi(m)^2}\sum_{a,b\in(\mathbb Z/m\mathbb Z)^\times}|E_{a,b,m}|.

Exceptional-set growth conjecture. As mm\to\infty,

Emax(m)=O(m2(logm)2),Lavg(m)=O(mε)for every ε>0.E_{\max}(m)=O\bigl(m^2(\log m)^2\bigr),\qquad L_{\mathrm{avg}}(m)=O(m^\varepsilon)\quad\text{for every }\varepsilon>0.

The conjecture is motivated by heuristic arguments and numerical data, which suggest roughly quadratic growth for Emax(m)E_{\max}(m). Analytic methods in the paper do not establish even finiteness of all the exceptional sets, so these bounds remain open.

Sources & referencesView supporting material

Primary source

Kimball Martin, “Refined Goldbach conjectures with primes in progressions”, arXiv:1806.00946 (2018).

Additional references

2 papers in this index state this conjecture (2015–2018). The statement above is taken from the most recent of them; the others are arXiv:1508.05967.

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