Conjecture on perfect powers in alternating sums of consecutive cubes

Let r=2dr=2d with 1d501\leq d\leq 50, let p5p\geq 5 be prime, and consider the equation

(x+1)3(x+2)3+(x+r)3+(x+r+1)3=zp.(x+1)^3-(x+2)^3+\cdots-(x+r)^3+(x+r+1)^3=z^p.

Here d,x,zd,x,z are integers. Alternating-cube perfect-power conjecture. The possible integer solutions are

(d,x,z,p){(2,2,2,7),(3,12,3,7),(6,14,6,5),(27,215,9,7)}.(d,x,z,p)\in\{(2,2,-2,7),(3,12,-3,7),(6,14,-6,5),(27,215,-9,7)\}.

This conjecture concerns perfect powers represented by alternating sums of an even number of consecutive cubes. The supplied text gives examples and restricts d50d\leq 50, but gives no resolution status for the asserted list.

Sources & referencesView supporting material

Primary source

Pranabesh Das, Pallab Kanti Dey, B. Maji and S. S. Rout, “Perfect powers in alternating sum of consecutive cubes”, arXiv:1705.02597 (2017).

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