Conjecture on perfect powers in alternating sums of consecutive cubes

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Let r=2dr=2d with 1≤d≤501\leq d\leq 50, let p≥5p\geq 5 be prime, and consider the equation

(x+1)3−(x+2)3+⋯−(x+r)3+(x+r+1)3=zp.(x+1)^3-(x+2)^3+\cdots-(x+r)^3+(x+r+1)^3=z^p.

Here d,x,zd,x,z are integers. Alternating-cube perfect-power conjecture. The possible integer solutions are

(d,x,z,p)∈{(2,2,−2,7),(3,12,−3,7),(6,14,−6,5),(27,215,−9,7)}.(d,x,z,p)\in\{(2,2,-2,7),(3,12,-3,7),(6,14,-6,5),(27,215,-9,7)\}.

This conjecture concerns perfect powers represented by alternating sums of an even number of consecutive cubes. The supplied text gives examples and restricts d≤50d\leq 50, but gives no resolution status for the asserted list.

References

Primary source

Pranabesh Das, Pallab Kanti Dey, B. Maji and S. S. Rout, “Perfect powers in alternating sum of consecutive cubes”, arXiv:1705.02597 (2017).

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