Polynomial representation conjecture for the odd-power binomial sums

Let a,b,ca,b,c be non-negative integers and, for rZ+r\in\mathbb{Z}^+, define

Sr(a,b,c):=k=0ak2r+1(a+ba+k)(b+cb+k)(c+ac+k).S_r(a,b,c):=\sum_{k=0}^a k^{2r+1}\binom{a+b}{a+k}\binom{b+c}{b+k}\binom{c+a}{c+k}.

Let L\mathcal{L} act on functions of a,b,ca,b,c by

Lf=[(a+b)(a+c)Ea2I]f,\mathcal{L}\cdot f=[(a+b)(a+c)E-a^2I]f,

where Ef(a,b,c)=f(a1,b,c)E\cdot f(a,b,c)=f(a-1,b,c) and If(a,b,c)=f(a,b,c)I\cdot f(a,b,c)=f(a,b,c). Polynomial representation conjecture. For each rZ+r\in\mathbb{Z}^+, there exist symmetric polynomials fr,grZ[a,b,c]f_r,g_r\in\mathbb{Z}[a,b,c] such that

Sr(a,b,c)=b2c2fr(a,b,c)(b+cb)2j=0a1(b+jb)(c+jc)gr(j+1,b,c)fr(j,b,c)fr(j+1,b,c).S_r(a,b,c)=\frac{b^2c^2f_r(a,b,c)\binom{b+c}{b}}{2}\sum_{j=0}^{a-1}\frac{\binom{b+j}{b}\binom{c+j}{c}\,g_r(j+1,b,c)}{f_r(j,b,c)f_r(j+1,b,c)}.

The polynomials frf_r satisfy

fr(a,b,c)=Lfr1(a,b,c),f0(a,b,c)=1.f_r(a,b,c)=\mathcal{L}\cdot f_{r-1}(a,b,c),\qquad f_0(a,b,c)=1.

The claim proposes a structured symmetric-polynomial form for these binomial sums and recursively determines the denominator polynomials. The surrounding text presents it as a problem, and a postscript reports that Matthew Hongye Xie had found a proof; the database status is therefore left open because the supplied parser status is unknown.

Sources & referencesView supporting material

Primary source

Tewodros Amdeberhan, David Callan, Hideyuki Ohtsuka and Roberto Tauraso, “Revitalized automatic proofs: demonstrations”, arXiv:1610.09737 (2016).

Progress summary

Never refreshed

Nothing recorded yet. Refresh searches the literature and the public web for attempts on this problem, and writes the first summary here.

Solutions 0

No solutions have been posted yet.