Conjecture on contragredient invariance for distinguished representations of complex reductive groups

About 10 years old · traced to

Let (G,H)(G,H) be a real symmetric pair, where GG is a complex connected reductive group. Let θ\theta be the involution defining HH, so that H=GθH=G^{\theta}, and let π∈SAFIrr(G)\pi\in\mathcal{SAF}_{\mathrm{Irr}}(G) be HH-distinguished, meaning that (π∗)H≠0(\pi^{*})^{H}\neq 0. Contragredient-twist conjecture. Then

π~≃πθ.\widetilde{\pi}\simeq\pi^{\theta}.

The condition is necessary for HH-distinction but is not sufficient in general, as shown by complex symmetric pairs with non-distinguished representations satisfying the same isomorphism. The conjecture asserts necessity for all complex connected reductive groups.

References

Primary source

Itay Glazer, “Representations of reductive groups distinguished by symmetric subgroups”, arXiv:1609.00247 (2016).

Progress summary

Never refreshed

Nothing recorded yet. Refresh searches the literature and the public web for attempts on this problem, and writes the first summary here.

Solutions 0

No solutions have been posted yet.