Conjecture on Legendre-symbol control of Gaussian-prime walk equivalence

Let a+bia+bi be a Gaussian prime and let qp\frac{q}{p} be the Legendre symbol appearing in the comparison of the two Gaussian-prime ratios a+biβ+βi\frac{a+bi}{\beta+\beta i} and a+biβ+βi\frac{a+bi}{\beta+\beta i}; the source's displayed expressions are retained below in the claim. Equivalence conjecture. The equivalence between the two corresponding bracketed quantities depends only on the value of the Legendre symbol qp\frac{q}{p}. In particular,

[a+biα+βi]=[a+biβ+αi]\left[\dfrac{a+bi}{\alpha+\beta i}\right] = \left[\dfrac{a+bi}{\beta+\alpha i}\right]

if qp=1\frac{q}{p}=1, and

[a+biα+βi][a+biβ+αi]\left[\dfrac{a+bi}{\alpha+\beta i}\right] \not= \left[\dfrac{a+bi}{\beta+\alpha i}\right]

if qp1\frac{q}{p}\not=1. This conjecture is proposed to explain the observed strong positive and negative correlations in the Gaussian-prime random walks; the source does not establish its status beyond leaving the equivalence conditions as a conjecture.

Sources & referencesView supporting material

Primary source

Daniel Hutama, “Modeling Chebyshev's Bias in the Gaussian Primes as a Random Walk”, arXiv:1608.08647 (2016).

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