Quantum geometric Langlands conjecture

Let GG be a complex reductive group, let XX be a smooth complex projective curve, and let GG^{\vee} be its Langlands dual group. Let det\mathfrak{\det} denote the determinant line bundle, let Dk(BunG(X))\mathcal D_k(Bun_G(X)) and Dk(BunG(X))\mathcal D_{k^{\vee}}(Bun_{G^{\vee}}(X)) be the categories of twisted D\mathcal D-modules at levels kk and kk^{\vee}, and impose k=1/kk^{\vee}=-1/k. Quantum geometric Langlands conjecture. There is an equivalence

Dk(BunG(X))Dk(BunG(X)),k=1/k.\mathcal D_k(Bun_G(X))\simeq \mathcal D_{k^{\vee}}(Bun_{G^{\vee}}(X)),\qquad k^{\vee}=-1/k.

The conjecture is a quantized form of de Rham geometric Langlands; the source explains its expected Hecke/localization compatibility and its degeneration to the usual de Rham conjecture as k0k\to0 and kk^{\vee}\to\infty.

Sources & referencesView supporting material

Primary source

David Ben-Zvi and David Nadler, “Betti Geometric Langlands”, arXiv:1606.08523 (2016).

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