Odd-length diagonal-twist spectral conjecture

Let NN be the length of the spin-one chain and let xx be its anisotropy parameter. Consider the Hamiltonian with diagonal twist and its eigenvalue degeneracies. Odd-length diagonal-twist conjecture. For odd NN and 0<x<20<|x|<\sqrt{2}, the Hamiltonian has a single negative, doubly degenerate ground-state eigenvalue; all other eigenvalues are non-negative, and the first excited state is the non-degenerate eigenvalue E=0E=0. For x=0x=0 or x2|x|\geq\sqrt{2}, the spectrum is non-negative and E=0E=0 is the ground-state eigenvalue, with degeneracy 2N+12N+1 for x=0x=0, three for x=2|x|=\sqrt{2}, and one for x>2|x|>\sqrt{2}. The claim is based on computed spectra and remains conjectural in the supplied text.

Sources & referencesView supporting material

Primary source

Christian Hagendorf and Alexi Morin-Duchesne, “Symmetry classes of alternating sign matrices in the nineteen-vertex model”, arXiv:1601.01859 (2016).

Progress summary

Never refreshed

Nothing recorded yet. Refresh searches the literature and the public web for attempts on this problem, and writes the first summary here.

Solutions 0

No solutions have been posted yet.