Conjecture on the number of inequivalent abelian squares
Conjecture on the number of inequivalent abelian squares
Two abelian squares are inequivalent when they have different Parikh vectors. Inequivalent-abelian-square bound conjecture. Every word of length contains inequivalent abelian squares. Computations support this asymptotic upper bound, while the paper notes that examples with order inequivalent abelian squares exist.
Sources & referencesView supporting material
Primary source
Gabriele Fici and Filippo Mignosi, “Words with the Maximum Number of Abelian Squares”, arXiv:1506.03562 (2015).
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