Unimodality of rectangular Narayana numbers

Let N(n,m;k1)N(n,m;k\mid 1) denote the rectangular Narayana numbers, indexed by 0k(n1)(m1)0\le k\le (n-1)(m-1). The sequence is symmetric about its midpoint. Rectangular Narayana unimodality conjecture. If 1k(n1)(m1)/21\le k\le (n-1)(m-1)/2, then

N(n,m;k11)N(n,m;k1),N(n,m;k-1\mid 1)\le N(n,m;k\mid 1),

i.e. the sequence {N(n,m;k1)}k=0(n1)(m1)\{N(n,m;k\mid 1)\}_{k=0}^{(n-1)(m-1)} is symmetric and unimodal. This asserts unimodality of the rectangular Narayana distribution; the supplied text gives no resolution status.

Sources & referencesView supporting material

Primary source

A. N. Kirillov, “Rigged Configurations and Catalan, Stretched Parabolic Kostka Numbers and Polynomials: Polynomiality, Unimodality and Log-concavity”, arXiv:1505.01542 (2015).

Progress summary

Never refreshed

Nothing recorded yet. Refresh searches the literature and the public web for attempts on this problem, and writes the first summary here.

Solutions 0

No solutions have been posted yet.