Sharp Poisson transform inequality on the Heisenberg group

At least 10 years old · documented by

Let nn be a positive integer, let aa satisfy −2n<a<0-2n<a<0, and let PaP_a be the Poisson transform from H2n−1H^{2n-1} to H2n+1H^{2n+1}. Set

p=4n2n+a,q=4n+42n+a.p=\frac{4n}{2n+a},\qquad q=\frac{4n+4}{2n+a}.

Sharpness and optimizer conjecture. There exists a sharp constant C>0C>0 such that

∥Paf∥Lq(H2n+1)≤C∥f∥Lp(H2n−1),\|P_af\|_{L^q(H^{2n+1})}\leq C\|f\|_{L^p(H^{2n-1})},

and the optimizers are translations, dilations, and multiples of the function

f(z′,t′)=((1+∣z′∣2)2+t′2)−a+2n4.f(z',t')=((1+|z'|^2)^2+t'^2)^{-\frac{a+2n}{4}}.

This conjecture asks for the sharp endpoint inequality associated with the Poisson transform in the Heisenberg setting and a classification of all optimizers. The surrounding discussion states that the corresponding result is known in the real case, while its Heisenberg analogue is open.

References

Primary source

Jan Möllers, Bent Ørsted and Genkai Zhang, “On boundary value problems for some conformally invariant differential operators”, arXiv:1503.01695 (2015).

Progress summary

Never refreshed

Nothing recorded yet. Refresh searches the literature and the public web for attempts on this problem, and writes the first summary here.

Solutions 0

No solutions have been posted yet.