A generalized Prouhet–Thue–Morse divisibility conjecture

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Let m1m\geq 1 and let a1,,aka_{1},\ldots,a_{k} be nonnegative integers. Put A=(a1,,ak)A=(a_{1},\ldots,a_{k}), X=(x1,,xm)X=(x_{1},\ldots,x_{m}), and Y=(y1,,ym)Y=(y_{1},\ldots,y_{m}). Define

GA(X,Y)=i1=0ka11ik=0kam1ζkj=1msk(ij)(j=1m(sk(ij)xj+ijyj))j=1maj.G_{A}(X,Y)=\sum_{i_{1}=0}^{k^{a_{1}}-1}\cdots\sum_{i_{k}=0}^{k^{a_{m}}-1}\zeta_{k}^{\sum_{j=1}^{m}s_{k}(i_{j})}\Bigl(\sum_{j=1}^{m}(s_{k}(i_{j})x_{j}+i_{j}y_{j})\Bigr)^{\sum_{j=1}^{m}a_{j}}.

Generalized Prouhet–Thue–Morse divisibility conjecture. If k=2k=2, then

GA(X,Y)=(1)j=1maj(j=1maj)!j=1mij=0aj1(xj+2ijyj).G_{A}(X,Y)=(-1)^{\sum_{j=1}^{m}a_{j}}\Bigl(\sum_{j=1}^{m}a_{j}\Bigr)!\prod_{j=1}^{m}\prod_{i_{j}=0}^{a_{j}-1}(x_{j}+2^{i_{j}}y_{j}).

If k>2k>2, then

j=1mij=0nj1(xj+kijyj)GA(X,Y).\prod_{j=1}^{m}\prod_{i_{j}=0}^{n_{j}-1}(x_{j}+k^{i_{j}}y_{j})\mid G_{A}(X,Y).

The conjecture is presented as a further generalization of results in the paper; the supplied text gives no resolution or supporting status evidence.

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Primary source

Jakub Byszewski and Maciej Ulas, “Some identities involving Prouhet-Thue-Morse sequence and its relatives”, arXiv:1409.8118 (2014).

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