Khesin–Soloviev higher-dimensional pentagram Devron conjecture in dimension three

Let A=(Ai)A=(A_i) be a periodic sequence of 2n2n points in RP3\mathbb{RP}^3, with n4n\geq 4. For each ii, let the face at ii be the plane through three consecutive vertices, and let FF send AA to the sequence whose iith vertex is the intersection of the line through Ai1A_{i-1} and Ai+1A_{i+1} with the plane through Ai2,Ai,Ai+2A_{i-2},A_i,A_{i+2}. Suppose there are points P,QP,Q such that the faces of AA pass through PP or QQ in alternating fashion.

Khesin–Soloviev higher-dimensional pentagram Devron conjecture. If B=Fn3(A)B=F^{n-3}(A), then B1,B3,,B2n1B_1,B_3,\ldots,B_{2n-1} are coplanar, and B2,B4,,B2nB_2,B_4,\ldots,B_{2n} are also coplanar.

This is a conjectural Devron-property statement for the higher-dimensional pentagram map on general polygons in RP3\mathbb{RP}^3, rather than only corrugated polygons. Its status is presented as experimental and unresolved in the source.

Sources & referencesView supporting material

Primary source

Max Glick, “The Devron property”, arXiv:1312.6881 (2014).

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