Equivalence of metric regularity and strong metric regularity of the subdifferential
Let be both prox-regular and subdifferentially continuous at for , where is a local minimizer of . The subdifferential mapping is metrically regular at if and only if it is strongly metrically regular there.
Equivalence of metric regularity and strong metric regularity. Under these hypotheses, metric regularity and strong metric regularity of the subdifferential are the same notions.
For convex functions, for twice continuously differentiable functions, and for functions of the form with twice continuously differentiable and polyhedral convex, the equivalence is known; the conjecture concerns all prox-regular and subdifferentially continuous functions on finite-dimensional spaces.
References
Primary source
D. Drusvyatskiy, B. S. Mordukhovich and T. T. A. Nghia, “Second-order growth, tilt stability, and metric regularity of the subdifferential”, arXiv:1304.7385 (2013).
Progress summary
Nothing recorded yet. Refresh searches the literature and the public web for attempts on this problem, and writes the first summary here.
Solutions 0
No solutions have been posted yet.