The Relatively Prime Conjecture for factorial polynomials

For a,bN2{\bf a},{\bf b}\in\mathbb N^2 with ab{\bf a}\ne{\bf b}, write c=ab{\bf c}={\bf a}-{\bf b} and define, for nNn\in\mathbb N,

Pa,b,n(X)=k=0n(b1n+c1k)!(b2n+c2k)!k!(nk)!Xk.P_{{\bf a},{\bf b},n}(X)=\sum_{k=0}^n\frac{(b_1n+c_1k)!(b_2n+c_2k)!}{k!(n-k)!}X^k.

Relatively Prime Conjecture. For all such a,b{\bf a},{\bf b} and all nNn\in\mathbb N, the polynomials Pa,b,n(X)P_{{\bf a},{\bf b},n}(X) and Pa,b,n+1(X)P_{{\bf a},{\bf b},n+1}(X) have no common zero in C{\mathbb C}. By the theorem preceding it, this is equivalent to the Strong Factorial Conjecture for polynomials in two variables consisting of two monomials. The paper proves several special cases, leaving the general assertion open.

Sources & referencesView supporting material

Primary source

Eric Edo and Arno van den Essen, “The Strong Factorial Conjecture”, arXiv:1304.3956 (2013).

Progress summary

Never refreshed

Nothing recorded yet. Refresh searches the literature and the public web for attempts on this problem, and writes the first summary here.

Solutions 0

No solutions have been posted yet.