Kahn's five-value range conjecture for Hamming-cube homomorphisms

About 14 years old · traced to

Let QdQ_d be the dd-dimensional Hamming cube and let F{\cal F} be the set of graph homomorphisms f ⁣:V(Qd)→Zf\colon V(Q_d)\to{\bf Z} satisfying f(0‾)=0f(\underline{0})=0. For f∈Ff\in{\cal F}, write R(f)={f(v) ⁣:v∈V(Qd)}R(f)=\{f(v)\colon v\in V(Q_d)\}, and use the uniform probability measure on F{\cal F}.

Kahn's five-value range conjecture.

P(∣R∣>5)=e−Ω(d)andP(∣R∣=5)=Ω(1).{\bf P}(|R|>5)=e^{-\Omega(d)}\qquad\text{and}\qquad {\bf P}(|R|=5)=\Omega(1).

The conjecture gives the expected sharp typical range size after Kahn's earlier constant-range bound. It is proved in the present paper by asymptotically counting homomorphisms according to their range size.

References

Primary source

David Galvin, “On homomorphisms from the Hamming cube to Z”, arXiv:1206.3152 (2012).

Progress summary

Never refreshed

Nothing recorded yet. Refresh searches the literature and the public web for attempts on this problem, and writes the first summary here.

Solutions 0

No solutions have been posted yet.