Uniformity conjecture for measures with frame measures

Let μ\mu be a finite Borel measure on Rd\mathbb{R}^d. Say that μ\mu is translationally absolutely continuous if, for every Borel set FF in the support of μ\mu with μ(F)>0\mu(F)>0 and every aRda\in\mathbb{R}^d, the translated restricted measure TaμF+aT_a\mu|_{F+a} is absolutely continuous with respect to μ\mu. For α>0\alpha>0, define

K(α)={xsupp(μ):limr0logμ(Br(x))logr=α}.K(\alpha)=\left\{x\in\operatorname{supp}(\mu):\lim_{r\to0}\frac{\log\mu(B_r(x))}{\log r}=\alpha\right\}.

A measure has only one local dimension if all points in its support at which the local dimension exists have the same value. Uniformity conjecture. If μ\mu has a frame measure, then μ\mu must be translationally absolutely continuous and have only one local dimension. The conjecture expresses the expectation that a measure admitting a frame measure distributes its mass uniformly across its support. The source gives no examples with more than one local dimension and a frame measure, and no resolution is stated.

Sources & referencesView supporting material

Primary source

Dorin Ervin Dutkay and Chun-Kit Lai, “Uniformity of measures with Fourier frames”, arXiv:1202.6028 (2012).

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