Periodicity conjecture for weighted finite taking-no-breaking games

Let O=(n1n2nt,p1p2pt)O=(n_1n_2\dots n_t,p_1p_2\dots p_t) and P=(m1m2ml,q1q2ql)P=(m_1m_2\dots m_l,q_1q_2\dots q_l) be two finite taking-no-breaking octal games. Assume that at least one nsn_s is neither 00 nor 11, and that whenever nin_i and mjm_j are in {1,2,3}\{1,2,3\}, the corresponding scores satisfy pi=ip_i=i and qj=jq_j=j, while otherwise pi=qj=0p_i=q_j=0. Let kk be the largest entry in OO such that nk0,1n_k\neq 0,1. Taking-no-breaking periodicity conjecture. Then

Gs(n+2k+m)=Gs(n+m).\mathcal{G}_s(n+2k+_{\ell}m)=\mathcal{G}_s(n+_{\ell}m).

Here ++_{\ell} denotes disjunctive sum, and the conjecture asserts that the period is 2k2k even after adding the fixed game mm. The authors report strong computational evidence but say that proving the claim is surprisingly difficult; the conjecture is open in the supplied text.

Sources & referencesView supporting material

Primary source

Fraser Stewart, “Impartial Scoring Play Games”, arXiv:1202.4655 (2012).

Progress summary

Never refreshed

Nothing recorded yet. Refresh searches the literature and the public web for attempts on this problem, and writes the first summary here.

Solutions 0

No solutions have been posted yet.