The Mathieu moonshine conjecture for twisted elliptic genera

For each gM24g\in M_{24}, let Zg(τ,z){\cal Z}_g(\tau,z) have Fourier expansion

Zg(τ,z)=n0,Zcg(4n2)qny.{\cal Z}_g(\tau,z)=\sum_{n\geq0,\,\ell\in\mathbb{Z}}c_g(4n-\ell^2)q^ny^\ell.

Let K^=(=0K^41)(=0K^4)\hat K=\left(\bigoplus_{\ell=0}^{\infty}\hat K_{4\ell-1}\right)\bigoplus\left(\bigoplus_{\ell=0}^{\infty}\hat K_{4\ell}\right) be an infinite-dimensional, Z\mathbb{Z}-graded super (or virtual) M24M_{24}-module, and let strK^kg\operatorname{str}_{\hat K_k}g denote the supertrace.

Twisted elliptic-genus module conjecture. For k0,3(mod4)k\equiv0,3\pmod4 and k1k\geq-1, one has

cg(k)=strK^kg.c_g(k)=\operatorname{str}_{\hat K_k}g.

For k0k\neq0, K^k\hat K_k is even, of the form k^kk^k\hat k_k\oplus\hat k_k^* for a super representation k^k\hat k_k and its dual. This conjecture refines the Mathieu moonshine module picture by encoding the twisted K3K3 elliptic-genus coefficients as supercharacters; the displayed coefficients and corresponding modules are computed in the source, while the general module interpretation is the conjectural part.

Sources & referencesView supporting material

Primary source

Miranda C. N. Cheng and John F. R. Duncan, “The Largest Mathieu Group and (Mock) Automorphic Forms”, arXiv:1201.4140 (2012).

Progress summary

Never refreshed

Nothing recorded yet. Refresh searches the literature and the public web for attempts on this problem, and writes the first summary here.

Solutions 0

No solutions have been posted yet.