The profinite primitivity conjecture for free groups
Let be the free group of rank , and let be its free profinite completion. An element is primitive if it belongs to a basis of the relevant free group. The profinite primitivity conjecture. For every word ,
The source notes that primitivity in the discrete free group implies primitivity in its free profinite completion, and conjectures the converse. No resolution is supplied here.
References
Primary source
Doron Puder, “Primitive Words, Free Factors and Measure Preservation”, arXiv:1104.3991 (2012).
Progress summary
Never refreshed
Nothing recorded yet. Refresh searches the literature and the public web for attempts on this problem, and writes the first summary here.
Solutions 0
No solutions have been posted yet.