Exponential positivity conjecture for nonnegative matrices

Let CC be an r×rr\times r matrix with non-negative entries, define α!=i=1rαi!\boldsymbol{\alpha}!=\prod_{i=1}^r\alpha_i! for αNr\boldsymbol{\alpha}\in\mathbb{N}^r, and let T\underline{T} act by T(xα)=qαtCαxα\underline{T}(x^{\boldsymbol{\alpha}})=q^{\boldsymbol{\alpha}^{t}C\boldsymbol{\alpha}}x^{\boldsymbol{\alpha}}. Suppose that aα(q)N[q]a_{\boldsymbol{\alpha}}(q)\in\mathbb{N}[q] for αNr\boldsymbol{\alpha}\in\mathbb{N}^r and that

exp(bα(q)xαα!q1)=Texp(aα(q)xαα!q1).\exp\left(\frac{\sum b_{\boldsymbol{\alpha}}(q)\frac{x^{\boldsymbol{\alpha}}}{\boldsymbol{\alpha}!}}{q-1}\right)=\underline{T}\exp\left(\frac{\sum a_{\boldsymbol{\alpha}}(q)\frac{x^{\boldsymbol{\alpha}}}{\boldsymbol{\alpha}!}}{q-1}\right).

Exponential positivity conjecture. Then bα(q)N[q]b_{\boldsymbol{\alpha}}(q)\in\mathbb{N}[q] for every αNr\boldsymbol{\alpha}\in\mathbb{N}^r. The conjecture was proved by Markus Reineke for r=1r=1 and remains open for general rr.

Sources & referencesView supporting material

Primary source

Sergey Mozgovoy, “Motivic Donaldson-Thomas invariants and Kac conjecture”, arXiv:1103.2100 (2011).

Progress summary

Never refreshed

Nothing recorded yet. Refresh searches the literature and the public web for attempts on this problem, and writes the first summary here.

Solutions 0

No solutions have been posted yet.