Universality conjecture for inversion symmetry of WDVV tau functions

Let F(v)F(v) be a solution of the WDVV equations, let F^(v^)\hat F(\hat v) be its inversion, and let F~g\tilde{\mathcal F}_g and F^g\hat{\mathcal F}_g be the corresponding genus-gg free energies. Define

G=g1ϵ2g2(F~gF^g).\mathcal G=\sum_{g\geq 1}\epsilon^{2g-2}\left(\tilde{\mathcal F}_g-\hat{\mathcal F}_g\right).

Let w^n\hat w^n be the associated transformed field. Universality conjecture. The difference can be represented as

G=G1(w^n)+ϵ2G2(w^n)+ϵ4G3(w^n)+,\mathcal G=\mathcal G_1(\hat w^n)+\epsilon^2\mathcal G_2(\hat w^n)+\epsilon^4\mathcal G_3(\hat w^n)+\cdots,

where each Gk(w^n)\mathcal G_k(\hat w^n) is a differential polynomial in w^n\hat w^n, and the differential polynomials Gg\mathcal G_g do not depend on the particular solution F(v)F(v) of the WDVV equations. The genus-one calculation preceding the conjecture gives the initial transformation law, while the higher-genus universal differential-polynomial representation is left open.

Sources & referencesView supporting material

Primary source

Si-Qi Liu, Dingdian Xu and Youjin Zhang, “The Inversion Symmetry of the WDVV Equations and Tau Functions”, arXiv:1012.5708 (2013).

Progress summary

Never refreshed

Nothing recorded yet. Refresh searches the literature and the public web for attempts on this problem, and writes the first summary here.

Solutions 0

No solutions have been posted yet.