Infinitude conjecture for the second binomial gcd condition

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For a positive integer nn, define

G2(n)=gcd⁡(14n+1(4n+1n),(2n+1)(4n+1)).G_2(n)=\gcd\left(\frac{1}{4n+1}{4n+1\choose n},(2n+1)(4n+1)\right).

Second binomial gcd infinitude conjecture. There are infinitely many positive integers nn such that

G2(n)=1.G_2(n)=1.

The paper presents this as the analogue of the first gcd infinitude conjecture and reports computational evidence, while no proof is supplied.

References

Primary source

Victor J. W. Guo and Jiang Zeng, “Factors of sums and alternating sums involving binomial coefficients and powers of integers”, arXiv:1008.3316 (2011).

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