The subalgebra conjecture for thinned self-similar group algebras

Let GG be a self-similar group as described in the source, let A(G){\mathscr A}(G) be its thinned algebra with augmentation ideal ϖ\varpi, and define its associated graded algebra by

A(G)=n0ϖn/ϖn+1.\overline{{\mathscr A}(G)}=\bigoplus_{n\ge0}\varpi^n/\varpi^{n+1}.

Let L(G){\mathscr L}(G) be the associated self-similar Lie algebra. Subalgebra conjecture. Then L(G){\mathscr L}(G) is a subalgebra of A(G)\overline{{\mathscr A}(G)}. The claim places the self-similar Lie algebra inside the graded algebra arising from the thinned group algebra; the supplied text does not indicate whether it has been proved or disproved.

Sources & referencesView supporting material

Primary source

Laurent Bartholdi, “Self-similar Lie algebras”, arXiv:1003.1125 (2010).

Progress summary

Never refreshed

Nothing recorded yet. Refresh searches the literature and the public web for attempts on this problem, and writes the first summary here.

Solutions 0

No solutions have been posted yet.