The genuine mixed Schmidt conjecture for three weights

Let D\mathcal{D} be as above. For triples satisfying

0i,j,k1,i+j+k=1,0\leq i,j,k\leq 1,\qquad i+j+k=1,

let BadD(i,j,k)\mathbf{Bad}_{\mathcal{D}}(i,j,k) be the set of (x,y)R2(x,y)\in\mathbb{R}^2 for which there exists c(x,y)>0c(x,y)>0 such that

max{qD1/i,qx1/j,qy1/k}>c(x,y)q1qN,\max\left\{|q|_{\mathcal{D}}^{1/i},\|qx\|^{1/j},\|qy\|^{1/k}\right\}>c(x,y)q^{-1}\qquad\forall q\in\mathbb{N},

with the boundary cases interpreted as specified in the source. The genuine mixed Schmidt conjecture. For any (i1,j1,k1)(i_1,j_1,k_1) and (i2,j2,k2)(i_2,j_2,k_2) satisfying these conditions,

BadD(i1,j1,k1)BadD(i2,j2,k2).\mathbf{Bad}_{\mathcal{D}}(i_1,j_1,k_1)\cap\mathbf{Bad}_{\mathcal{D}}(i_2,j_2,k_2)\neq\emptyset.

The source explains that this interpolates between the classical Schmidt conjecture and the mixed Schmidt conjecture studied in the paper. It remains open in the stated generality.

Sources & referencesView supporting material

Primary source

Dzmitry Badziahin, Jason Levesley and Sanju Velani, “The mixed Schmidt conjecture in the theory of Diophantine approximation”, arXiv:1001.4445 (2010).

Progress summary

Never refreshed

Nothing recorded yet. Refresh searches the literature and the public web for attempts on this problem, and writes the first summary here.

Solutions 0

No solutions have been posted yet.