The combinatorial Sylvester four-point conjecture

From papers

Fix n4n\geq 4. Let w\mathsf{w} be a uniformly random reduced expression for the long word in SnS_n, and choose uniformly at random a 44-subset of {1,,n}\{1,\ldots,n\}. The induced reduced expression v\mathsf{v} for the long word in S4S_4 is compared with

X={s1s2s3s2s1s2, s3s2s1s2s3s2, s2s1s2s3s2s1, s2s3s2s1s2s3}.X=\{s_1s_2s_3s_2s_1s_2,\ s_3s_2s_1s_2s_3s_2,\ s_2s_1s_2s_3s_2s_1,\ s_2s_3s_2s_1s_2s_3\}.

Combinatorial Sylvester four-point conjecture. For every n4n\geq 4, the probability that vX\mathsf{v}\in X is 1/41/4.

This is a combinatorial analogue of Sylvester's four-point problem, obtained from the Goodman–Pollack classification of point configurations. A more general result of O. Angel and A. E. Holroyd is stated to imply this conjecture.

Progress summary

Nothing recorded yet. Refresh searches the literature and the public web for attempts on this problem, and writes the first summary here.

Sources & referencesView supporting material

Primary source

Gregory S. Warrington, “A combinatorial version of Sylvester's four-point problem”, arXiv:0910.5945 (2010).

Solutions 0

No solutions have been posted yet.