Uniqueness conjecture for Schottky projective structures

Fix a marking of the projective structure Ω/Γ\Omega/\Gamma on SS with Schottky holonomy ρ\rho. Let Pρ\mathcal{P}_\rho be the collection of projective structures on SS with holonomy ρ\rho and the same orientation as Ω/Γ\Omega/\Gamma. Let StabρStab_\rho be the subgroup of orientation-preserving mapping classes ϕ\phi satisfying ρϕ=ρ\rho\circ\phi^*=\rho, and let AMLρ(S)\mathcal{AML}_\rho(S) be the isotopy classes of multiloops consisting of disjoint admissible loops on Ω/Γ\Omega/\Gamma. For a mapping class ϕ\phi, write Supp(ϕ)\operatorname{Supp}(\phi) for its minimal subsurface of nontrivial action. Uniqueness conjecture. Every CPρC\in\mathcal{P}_\rho can be obtained by changing the marking of Ω/Γ\Omega/\Gamma by a unique ϕStabρ\phi\in Stab_\rho and grafting Ω/Γ\Omega/\Gamma along a unique LAMLρ(S)L\in\mathcal{AML}_\rho(S) such that LL and Supp(ϕ)\operatorname{Supp}(\phi) are disjoint; equivalently,

Pρ(S){(ϕ,L)Stabρ×AMLρ(S)Supp(ϕ)L=}.\mathcal{P}_{\rho}(S)\cong\{(\phi,L)\in Stab_{\rho}\times\mathcal{AML}_{\rho}(S)\mid \operatorname{Supp}(\phi)\cap L=\emptyset\}.

Theorem supplies such a pair without guaranteeing disjointness, so the conjecture asserts that the intersection can always be uniquely resolved. The subgroup StabρStab_\rho is known to be generated by Dehn twists along loops in ker(ρ)\ker(\rho), but the asserted uniqueness with disjoint support remains open.

Sources & referencesView supporting material

Primary source

Shinpei Baba, “Complex projective structures with Schottky holonomy”, arXiv:0906.0413 (2012).

Progress summary

Never refreshed

Nothing recorded yet. Refresh searches the literature and the public web for attempts on this problem, and writes the first summary here.

Solutions 0

No solutions have been posted yet.