The higher-dimensional volume comparison conjecture

From papers

Let (Sn,g0)(S^n,g_0) be the sphere with its constant-curvature metric, scalar curvature R0R_0, Ricci curvature represented by Ric0g0Ric_0\cdot g_0, and volume V0V_0. For each n3n\geq 3, let (Mn,g)(M^n,g) be a complete smooth Riemannian manifold of volume VV.

Higher-dimensional volume comparison conjecture. There exists a positive ϵ0(n)<1\epsilon_0(n)<1 such that, whenever

R(g)R0,R(g)\geq R_0, Ric(g)ϵ0(n)Ric0g,Ric(g)\geq\epsilon_0(n)\cdot Ric_0\cdot g,

then

VV0.V\leq V_0.

The claim generalizes the preceding volume comparison theorem from dimension three to all dimensions n3n\geq3; the source gives no resolution.

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Sources & referencesView supporting material

Primary source

Hubert L. Bray, “The Penrose inequality in general relativity and volume comparison theorems involving scalar curvature (thesis)”, arXiv:0902.3241 (2009).

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