Generalization of Beardon’s theorem to tame rational functions
Let be a field of characteristic , and let be a rational function over whose degree is not a multiple of . For a rational function , write for its group of compositional symmetries. The preceding theorem asserts that for tame polynomials , if are the orders of , respectively, then divides . Generalized Beardon conjecture. Theorem is true for every rational function whose degree is not a multiple of the characteristic of the field. The conjecture would extend the divisibility result from tame polynomials to rational functions; the preceding example shows that the polynomial proof does not directly generalize in the rational case because fields of the same degree need not be unique.
References
Primary source
Jaime Gutierrez and David Sevilla, “On decomposition of tame polynomials and rational functions”, arXiv:0804.1649 (2008).
Progress summary
Nothing recorded yet. Refresh searches the literature and the public web for attempts on this problem, and writes the first summary here.
Solutions 0
No solutions have been posted yet.