Hilbert's 12th problem

Let KK be an algebraic number field (a finite extension of Q\mathbb{Q}) with a fixed algebraic closure K\overline{K}, and let

Kab={L:  KLK,  [L:K]<,  Gal(L/K) abelian}K^{\mathrm{ab}}=\bigcup\{\,L:\;K\subseteq L\subseteq\overline{K},\;[L:K]<\infty,\;\operatorname{Gal}(L/K)\ \text{abelian}\,\}

be the maximal abelian extension of KK.

For every such KK there exist analytic (transcendental) functions fif_i of one or several complex variables, given by explicit analytic expressions attached to KK alone, and an explicitly described set SiS_i of arguments in the domain of each fif_i, arising from KK-rational data (elements of KK, lattices or period data attached to KK, and torsion points of the associated analytic groups), such that every value fi(s)f_i(s) with sSis\in S_i is algebraic over KK and

Kab=K(fi(s)  :  iI,  sSi),K^{\mathrm{ab}}=K\bigl(f_i(s)\;:\;i\in I,\;s\in S_i\bigr),

with, in addition, an explicit description of the action of Gal(Kab/K)\operatorname{Gal}(K^{\mathrm{ab}}/K) on these special values, so that for each finite abelian extension L/KL/K a finite subset of the values generating LL over KK can be exhibited.

The shape of the required data is fixed by the following two instances. For K=QK=\mathbb{Q} one may take f(z)=e2πizf(z)=e^{2\pi i z} and S=QS=\mathbb{Q}, so that Qab=Q(e2πi/n:n1)\mathbb{Q}^{\mathrm{ab}}=\mathbb{Q}\bigl(e^{2\pi i/n}:n\ge 1\bigr). For K=Q(τ)K=\mathbb{Q}(\tau) imaginary quadratic with Imτ>0\operatorname{Im}\tau>0, one may take the elliptic modular function jj, the Weierstrass function z(τ,z)z\mapsto\wp(\tau,z) associated with the lattice Z+Zτ\mathbb{Z}+\mathbb{Z}\tau, and the exponential function: KabK^{\mathrm{ab}} is generated over KK by j(τ)j(\tau), by the values (τ,z)\wp(\tau,z) at the torsion points zz of C/(Z+Zτ)\mathbb{C}/(\mathbb{Z}+\mathbb{Z}\tau), and by the roots of unity.

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Sources & referencesView supporting material

Primary source

Wikipedia

Additional references

  1. Wikipedia, Hilbert's twelfth problem, the article this problem comes from.

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