Hilbert's 11th problem

Let KK be an algebraic number field, i.e. a finite extension of Q\mathbb{Q}, and let OK\mathcal{O}_K denote its ring of integers.

For n1n \ge 1, consider the quadratic forms

Q(x1,,xn)=i,j=1naijxixj,aij=aji,Q(x_1,\dots,x_n) = \sum_{i,j=1}^{n} a_{ij} x_i x_j, \qquad a_{ij} = a_{ji},

with coefficients aijKa_{ij} \in K (respectively aijOKa_{ij} \in \mathcal{O}_K), and assume det(aij)0\det(a_{ij}) \neq 0.

Call two such forms Q,QQ, Q' in nn variables

  • KK-equivalent if there is TGLn(K)T \in \mathrm{GL}_n(K) with Q(x)=Q(Tx)Q'(x) = Q(Tx) for all xx; - OK\mathcal{O}_K-equivalent if both have coefficients in OK\mathcal{O}_K and there is TGLn(OK)T \in \mathrm{GL}_n(\mathcal{O}_K) (that is, TT with entries in OK\mathcal{O}_K and detTOK×\det T \in \mathcal{O}_K^{\times}) with Q(x)=Q(Tx)Q'(x) = Q(Tx) for all xx.

Give a complete classification of these forms up to KK-equivalence and up to OK\mathcal{O}_K-equivalence: exhibit, for each nn, a system of invariants of QQ attached to KK (and to OK\mathcal{O}_K) that can be computed from the coefficients aija_{ij} and that determines the equivalence class of QQ, so that for any two given forms it can be decided whether they are equivalent, and describe which systems of invariant values actually occur.

Solve, in the same terms, the associated representation problem: for a given form QQ as above and a given element cc of KK (respectively of OK\mathcal{O}_K), decide from such invariants whether the equation

Q(x1,,xn)=cQ(x_1,\dots,x_n) = c

has a solution with x1,,xnKx_1,\dots,x_n \in K (respectively with x1,,xnOKx_1,\dots,x_n \in \mathcal{O}_K), and more generally determine the set of cc represented by QQ over KK and over OK\mathcal{O}_K; the case c=0c = 0 with (x1,,xn)(0,,0)(x_1,\dots,x_n) \neq (0,\dots,0) is included.

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Sources & referencesView supporting material

Primary source

Wikipedia

Additional references

  1. Wikipedia, Hilbert's eleventh problem, the article this problem comes from.

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